বুঝাও (Teach Me)

RAID -> Redundant Array of Independent Disks -> It is a method in which multiple hard disks are placed in parallel and are controlled as if they were one disk unit -> It has 6 Levels RAID0 to RAID6 RAID Levels -> RAID0 : Writes block of fixed size in multiple disks. -> RAID1 : Records same data on two disk for safety. -> RAID2 : Correct error -> RAID3 and RAID4 : Detect error -> RAID5 : each data block is assigned a parity value. Upon failure of a single drive, subsequent reads can be calculated from the distributed parity such that no data is lost. -> RAID6 : extends RAID 5 by adding another parity block. the data is recoverable even when two disks fail.

Reverse Polish Notation -> Take e = a – b ÷ ( c + d ) -> Lets convert it into Reverse Polish Notation -> ( c + d ) will be cd+ and Let p = cd+ -> e = a – b ÷ p -> b ÷ p will be bp÷ and Let q = bp÷ -> e = a – q -> a – q will be aq- and Let r = aq- -> e = r -> e = r will be er= and let s = er= -> s -> Lets put the values back -> s will be er= -> er= will be eaq-= -> eaq-= will be eabp÷-= -> eabp÷-= will be eabcd+÷-= -> eabcd+÷-= Polish Notation -> Take e = a – b ÷ ( c + d ) -> Lets convert it into Polish Notation -> ( c + d ) will be +cd and Let p = +cd -> e = a – b ÷ p -> b ÷ p will be ÷ bp and Let q = ÷ bp -> e = a – q -> a – q will be -aq and Let r = -aq -> e = r -> e = r will be =er and let s = =er -> s  -> Lets put the values back -> s will be =er -> =er will be =e-aq -> =e-aq will be =e-a÷bp -> =e-a÷bp will be =e-a÷b+cd

Number Types Decimal Hex Octal Binary Possible Conversations Decimal <-> Binary Decimal <-> Octal Decimal <-> Hex Binary <-> Octal Binary <-> Hex Octal <-> Hex Decimal -> Binary -> Take decimal 49 -> 64 is big so -> 32 X (1/0) + 16 X (1/0) + 8 X (1/0) + 4 X (1/0) + 2 X (1/0) + 1 X (1/0) -> 32 X 1 + 16 X 1 + 8 X 0 + 4 X 0 + 2 X 0 + 1 X 1 -> 110001 Binary -> Decimal -> Take binary 110001 -> 32 X 1 + 16 X 1 + 8 X 0 + 4 X 0 + 2 X 0 + 1 X 1 -> 49 Decimal -> Octal -> Take decimal 49 -> 64 is big so -> 32 X (1/0) + 16 X (1/0) + 8 X (1/0) + 4 X (1/0) + 2 X (1/0) + 1 X (1/0) -> 32 X 1 + 16 X 1 + 8 X 0 + 4 X 0 + 2 X 0 + 1 X 1 -> 110001 -> divide into 3 digits -> 110 and  001 -> 6 and 1 -> 61 Octal -> Decimal -> Take octal 61 -> 6 and 1 -> convert into 3 digit bin